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# 高中数学人教B版必修1第二章《函数》章末质量评估

()

(90 120 )

( 12 5 60 )

1 f(x)

1 2x3

A(032)

B[32)

C(32]

D(32)

2x3>0

3 x>2.

( )

D 2 Af(x)x41 Bf(x)x2(1<x<3) Cf(x)x1x Df(x)xx4

( )

f(x)f(x) BCD

A

3 yx24x1x[2,5]

A[1,6]

B[3,1]

C[3,6]

D[3)

( )

y(x2)23[2) f(2)3 x

[2,5]f(5)6. C 4 Af(x)x2x6 (12] Bf(x) x[0)

( )

Cf(x)2x x() Df(x)x31 f(x)x2x6 (12] A f(x) x

2x [0)f(x) x (0)(0)f(x)

x31

A

5 f(x)(ax)|3ax|a a>0( )

A x2a 0

B x3a 0

C

D

x2a2a2 x3a

f(x)

x2a2a2 x>3a

C

C

6 f(x)1xx5

( )

A1

B2

C3

D4

f(x)0 1xx5 y1x yx5

f(x)1xx5

B

7 M{x|2x2}N{y|0y2} 4

M N

( )

M[2,2] A[0,2] D

C.

B

8|x|1 yax2a1 a ( )

Aa13

Ba1

C1a13

D

|x|1 yax2a1 f(1)f(1)0

(3a1)(a1)01a13 C.

C

9 R yf(x)[ab] yf(xa)

( )

A[2aab]

B[ab]

C[0ba]

D[aab]

yf(xa) yf(x)|a|

yf(x) yf(xa) B 10 f( 2x1)x22x f(3) A0 C2

( ) B1 D3

2x13 x2f(3)22220.

A 11 f(x) R (0) x1<0 x1x2>0
( ) Af(x1)>f(x2) Bf(x1)f(x2) Cf(x1)<f(x2) D f(x1) f(x2) x1<0 x1x2>0x1>x2

f(x)(0)f(x1)<f(x2)

f(x)f(x1)<f(x2)

C

12 yxk y2kx24xk2

( )

k<0 AB x1k<0 C.
D ( 4 5 20 ) 13 f(x)1x0 f(x)x1 0x1

f(x)________. 0x1 1x0f(x)x1.
f(x)f(x)x11x. 1x 14 f(x) f(xy)f(x)f(y)(xyR) ________ f(0)0 f(3)3f(1) f(12)12f(1) f(x)f(x)<0. xy0 f(0)0 x2y1 f(3)f(2)f(1)3f(1) xy12f(1)2f(12) f(12)12f(1) yx f(0)f(x)f(x) f(x)f(x) f(x)f(x)[f(x)]20. 15 f(x)x32x1 f(0)<0 f(0.5)>0 x0________ f(x) f(________) f(0)<0f(0.5)>0
00.5 (0,0,5) 2 0.25. (0,0.5) 0.25 16 f(x)x2(2a1)xa1 (1,2) a ________ f(x) x2a2 1a12
(1,2)

a122 a121

a52 a32.

a52 a32 ( 4 10 40 ) 17 f(x)x22(m2)xmm2. (1) f(2)0 m (2)[2) m (1)f(0)0f(2)0

2m22

mm20

m1.

(2)yf(x)[2)

x2m222

m0.

18 f(x)11xx22.

(1) f(x)

(2) f(x)

(3)f(1x)f(x)

(1) 1x20 x1

f(x){x|x1xR}

(2) f(x)

x{x|x1xR}

x{x|x1xR}

f(x)11xx2211xx22f(x)

f(x)

(3)

f(1x)1111xx2211xx1122xx221111xx22f(x)f(1x)f(x)

19 f(x)(2,2) g(x)f(x1)f(32x) (1) g(x) (2) f(x) g(x)0

2x12 (1)232x2

1x3 12x52.

12<x<52. f(x)1252. (2) g(x)0 f(x1)f(32x)0 f(x1)f(32x) f(x)f(x1)f(2x3) f(x)(2,2)

x12x3 12x52.

12x2. g(x)0 122. 20 f(x)x22xxax[1) (1) a12 f(x) (2) x[1)f(x)>0 a (1) a12f(x)x21x2 f(x)[1 )

f(x)[1) f(1)72. (2)[1)f(x)x22xxa>0 x22xa>0 yx22xax[1) yx22xa(x1)2a1 [1) x1 ymin3a. ymin3a>0 f(x)>0 a>3.